# NEET Physics Kinetic Theory of Gases Questions Solved

The mean free path of electrons in a metal is $4×{10}^{-8}m.$The electric field which can give on an average 2 eV energy to an electron in the metal will be in unit of $V{m}^{-1}$

(a) $8×{10}^{7}$                              (b) $5×{10}^{-11}$

(c) $8×{10}^{-11}$                          (d) $5×{10}^{7}$