NEET Physics Nuclei Questions Solved

NEET - 2010

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is 

(a) 23.6 MeV                                         (b) 2.2 MeV

(c) 28.0 MeV                                          (d) 30.2 MeV

Mass of 1H2=2.01478 amuMass of 2He4=4.00388 amuMass of two deuterium=2×2.01478                                        =4.02956 amuEnergy equivalent to 2H2                               =4.02956×1.2                               =4.4 MeVEnergy equivalent to 2He4                               =4.00388×7                                =28 MeVEnergy released=(28-4.4)                             =23.6 MeV

Difficulty Level:

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