NEET Questions Solved

NEET - 2010

A vibration magnetometer placed in magnetic meridian has a small bar magnet. The magnet executes oscillations with a time period of 2s in earth's horizontal magnetic field of 24 μT. When a horizontal field is 18 μT is produced opposite to the earth's field by placing a current carrying wire, the new time period of magnet will be

(a) 1s          (b) 2s

(c) 3s          (d) 4s

Time period in vibration magnetometer

             T=2πIM×BH

       T1BH

       T1T2=(BH)2(BH)1

       2T2=1824

             T=2.3s = 2s

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