# NEET Questions Solved

NEET - 2010

The energy of a hydrogen atom in the ground state is -13.6 eV. The energy of a ${\mathrm{He}}^{+}$ ion in the first excited state will be

(a) -13.6 eV

(b) -27.2 eV

(c) -54.4 eV

(d) -6.8 eV

Energy E of an atom with principal quantum number n is given by E=$\frac{-13.6}{{n}^{2}}{Z}^{2}$ for first excited state n=2 and for

=-13.6 eV

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