Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and B is moving with velocity v along x-axis. After collision B has a velocity v2 in a direction perpendicular to the original direction.The mass A moves after collision in the direction

(a)same as that of B

(b)opposite to that of B

(c)θ=tan-112to the xaxis

(d)θ=tan-1-12to the xaxis

Concept Videos :-

#4 | Definition of Momentum
#5 | Conservation of Momentum
#6 | Problems

Concept Questions :-

Linear momentum

Here,Pi=m2vi+m2×0

Pf=m2v2j+m1×v2

Law of conservation of momentum

Pi=Pf

v2=m2m1vi-m2m1v2j

From this equation we can find 

tanθ=-12

θ=tan-1-12to the x-axis.

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