NEET Physics Atoms Questions Solved

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NEET - 2015

In the spectrum of hydrogen. the ratio of the longest wavelength in the Lyman series to the longest wavelength in the Balmer series is:-

(a) 4/9
(b) 9/4
(c) 27/5
(d) 5/27

In hydrogen atom, wavelength of characteristic spectrum

1λ=Rz2 [1/n12-1/n22]

For Lyman series n1=1 , n2=2

1λ1=Rz2[1/(1)2-1/(2)2] …(i)

For Balmer series n1=2, n2=3

1λ2=Rz2 [1/(2)2-1(3)2] … (ii)

Dividing Eq. (ii) by Eq. (i) we get

λ1λ2=Rz2 [1/4-1/9] =   5/36
          Rz2 [1-1/4]       3/4

λ1λ2=5/36 x 4/3 =5/27

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