An n-p-n transistor is connected in the common base configuration in a given amplifier. A load resistance of 800Ω is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuits is 192 Ω the voltage gain and the power gain of the amplifier will respectively be

1. 3.69,3.84
2. 4,4
3. 4,3.69
4. 4,3.84

If in a p-n junction, a square input signal of 10 V is applied as shown, then the output across R_L will be:
              

1.		2.
3.		4.

In the given figure, a diode D is connected to an external resistance R = 100 Ω  and an e.m.f of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current in the circuit will be


1. 30mA

2. 40mA

3. 20mA

4. 35mA

The input signal given to a CE amplifier having a voltage gain of 150 is V_i=2cos(15t+π/3). The corresponding output signal will be

(a)300cos(15t+π/3)

(b)75cos(15t+2π/3)

(c)2cos(15t+5π/3)

(d)300cos(15t+4π/3)

The given graph represents the V-I characteristic for a semiconductor device. Which of the following statement is correct?

The barrier potential of a p-n junction depends on

(i)type of semiconductor material

(ii)amount of doping

(iii)temperature

Which one of the following is correct

1. (i) and (ii)only

2. (ii) only

3. (ii) and (iii)only

4. (i),(ii) and (iii)

In a n-type semiconductor, which of the following statement is true ?

(a) Electrons are majority carriers and trivalent atoms are dopants

(b) Electrons are minority carriers and pentavalent atoms are dopants

(c) Holes are minority carriers and pentavalent atoms are dopants

(d) Holes are majority carriers and trivalent atoms are dopants

In a common emitter (CE) amplifier having a voltage gain G, the transistor used has transconductance 0.03 mho and current gain 25. If the above transistor is replaced with another one with transconductance 0.02 mho and current gain 20, the voltage gain will 

(a)$\frac{2}{3}G$                                       (b)$1.5G$

(c)$\frac{1}{3}G$                                        (d)$\frac{5}{4}G$

The output (x) of logic circuit shown in figure will be 

(1) $X=\stackrel{=}{A}·\stackrel{=}{B}$

(2) $X=\overline{A.B}$

(3)$X=A·B$

(4)$X=\overline{A+B}$

Two ideal diodes are connected to a battery as shown in the circuit. The current supplied by the battery is

(1)0.75A                             

(2)zero

(3)0.25A                               

(4)0.5A