NEET Physics Alternating Current Questions Solved

NEET - 2016

A filament bulb (500 W,100 V) is to be used in a 230 V main supply. When a resistance R is connected in series, it works perfectly and the bulb consumes 500 W. The value of R is 

(a) 230Ω          (b) 46Ω

(c) 26Ω            (d) 13Ω

(c) If a rated voltage and power are given,

 then   Prated=Vrated2R

Current in the bulb, i=PV


Resistance of bulb, Rb=100×100500=20Ω

Resistance R is connected in series.


 R+20=2305=46   R=26Ω 

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