Which statement is true about the most stable Lewis structure for $C{S}_{2}$ ?

(a) There are no lone pairs in molecule

(b) All bonds are double bonds

(c) The central atom does not have an octet of electrons

(d) A sulfur atom must be the central atom for the stucture to be stable

Concept Questions :-

Covalent Bonding
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Minimum $\mathrm{F}—\mathrm{S}—\mathrm{F}$ bond angle present in:

(a)                                                      (b) ${\mathrm{SF}}_{6}$

(c) ${\mathrm{SF}}_{2}$                                                        (d) ${\mathrm{F}}_{3}\mathrm{SSF}$

Concept Questions :-

Hybridisation
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

$Sb{F}_{5}$ reacts with $Xe{F}_{4}$ and $Xe{F}_{6}$ to form ionic compounds $\left[Xe{{F}_{3}}^{+}\right]$ $\left[Sb{{F}_{6}}^{-}\right]$ and $\left[Xe{{F}_{5}}^{+}\right]$ $\left[Sb{{F}_{6}}^{-}\right]$ then molecular shape of $\left[Xe{{F}_{3}}^{+}\right]$ ion and $\left[Xe{{F}_{5}}^{+}\right]$ ion respectively :

(a) Square pyramidal, T-shaped

(b) Bent T-shape, Square pyramidal

(c) See- saw , square pyramidal

(d) Square pyramidal , See-saw

Concept Questions :-

Hybridisation
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

In which of the following species maximum atom can lie in same plane?

(a) $Xe{F}_{2}{o}_{2}$

(b) $PC{l}_{5}$

(c)$As{{H}_{4}}^{+}$

(d) $Xe{F}_{4}$

Concept Questions :-

Hybridisation
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If two different non axial d-orbitals having 'xz' nodal plane form $\mathrm{\pi }$ bond by overlaping each other then internuclear axis will be :

(a) x         (b) y

(c) z         (d) They don't form $\mathrm{\pi }$ bond

Concept Questions :-

Covalent Bonding
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The geometry of ammonia molecule can be best described as:

(a) Nitrogen at one vertex of a regular tetrahedron, the other three vertices being occupied by three hydrogens

(b) Nitrogen at the centre of the tetrahedron, three vertics being occupied by three hydrogens

(c) Nitrogen at the centre of an equilateral triangle, three corners being occupied by three hydrogens

(d) Nitrogen at the junction of a T, three open ends being occupied by three hydrogens

Concept Questions :-

Hybridisation
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Assuming pure 2s and 2p orbitals are carbon are used in forming $C{H}_{4}$ molecule, which of the following statements is false?

(a) Three C$—$H bonds will be at right angle

(b) One C$—$H bond will be weaker then other three C$—$H bonds

(c) The shape of molecule will be tetrahedral

(d) The angle of C$—$H bond formed by s-s overlapping will be uncertain with respect to other three bonds

Concept Questions :-

Hybridisation
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Which molecular geometry is least likely to result from a trigonal bipyramidal electron geometry?

(a) Trigonal planar

(b) See-saw

(c) Linear

(d) T-shaped

Concept Questions :-

Hybridisation
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Which of the following orbital can not form $\mathrm{\pi }$ as well as $\delta$-bond?

(a) ${d}_{xy}$                    (b) ${d}_{{z}^{2}}$

(c) ${d}_{{x}^{2}-{y}^{2}}$               (d) ${d}_{yz}$

High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Give the correct order of initials and F for following statements. use T if statement is true and F if it is false :

(a) The order of repulsion betweeen different pair of electrons is ${l}_{p}-{l}_{p}>{l}_{p}-{b}_{p}>{b}_{p}-{b}_{p}$

(b) In general , as the number of lone pair of electrons on central atom increases, value of bond angle from normal bond angle also increases

(c) The number of lone pair on O in ${H}_{2}O$ is 2 while on N in $N{H}_{3}$ is 1

(d) The structure of xeon fluorides and xenon oxyfluorides could not be explained on the basis of VSEPR

(A) TTTF

(B) TFTF

(C) TFTT

(D) TFFF

Concept Questions :-

V.S.E.P.R