Q. No.The speed \((s)\) of a car as a function of time \((t)\) is shown figure, The distance travelled by the car in \(8\) seconds is:
1. \(180~\text{m}\)
2. \(60~\text{m}\)
3. \(80~\text{m}\)
4. \(18~\text{m}\)
A body is falling freely in a resistive medium. The motion of the body is described by \(\dfrac{dv}{dt}=(4-2v), \) where \(v\) is the velocity of the body at any instant (in \(\text{ms}^{–1}\)). The terminal velocity in this case refers to the velocity the body approaches as time \(t \to \infty.\) The initial acceleration and terminal velocity of the body, respectively, are:
| 1. | \(4~\text{m/s}^2,\) \(2~\text{m/s}\) | 2. | \(2~\text{m/s}^2,\) \(4~\text{m/s}\) |
| 3. | \(6~\text{m/s}^2,\) \(2~\text{m/s}\) | 4. | \(2~\text{m/s}^2,\) \(6~\text{m/s}\) |
| 1. | \(5~\text{m}\) | 2. | \(25~\text{m}\) |
| 3. | \(45~\text{m}\) | 4. | \(58~\text{m}\) |
The acceleration \((a)\)-time \((t)\) graph that best suits this motion is:
| 1. |  |
2. |  |
| 3. |  |
4. |  |
| 1. | \(68\) m | 2. | \(56\) m |
| 3. | \(60\) m | 4. | \(64\) m |
| 1. | \(\dfrac{3v}{4}\) | 2. | \(\dfrac{v}{3}\) |
| 3. | \(\dfrac{2v}{3}\) | 4. | \(\dfrac{4v}{3}\) |
The figure given below shows the displacement and time, \((x\text -t)\) graph of a particle moving along a straight line:
The correct statement, about the motion of the particle, is:
| 1. | the particle moves at a constant velocity up to a time \(t_0\) and then stops. |
| 2. | the particle is accelerated throughout its motion. |
| 3. | the particle is accelerated continuously for time \(t_0\) then moves with constant velocity. |
| 4. | the particle is at rest. |
A stone is thrown vertically downwards with an initial velocity of \(40\) m/s from the top of a building. If it reaches the ground with a velocity of \(60\) m/s, then the height of the building is: (take \(g=10\) m/s2)
| 1. | \(120\) m | 2. | \(140\) m |
| 3. | \(80\) m | 4. | \(100\) m |
1. \(1:1:1:1\)
2. \(1:2:3:4\)
3. \(1:4:9:16\)
4. \(1:3:5:7\)
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