The equivalent weight of phosphoric acid (H3PO4) in the reaction $NaOH+{H}_{3}P{O}_{4}\to Na{H}_{2}P{O}_{4}+{H}_{2}O$ is [AIIMS 1999]

(1) 25

(2) 49

(3) 59

(4) 98

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What is the equivalent mass of $I{O}_{4}^{-}$ when it is converted into I2 in acid medium [Kerala PMT 2004]

(1) M/6

(2) M/7

(3) M/5

(4) M/4

Concept Questions :-

Equivalent Weight & Normality
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In alkaline medium ClO2 oxidize H2O2 in O2 and reduced itself in Cl then how many mole of H2O2 will oxidize by one mole of ClO2

1. 1.0

2. 1.5

3. 2.5

4. 3.5

Concept Questions :-

Balancing of Equation by Ion Exchange Method
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Oxidation number of oxygen in potassium super oxide (KO2) is [UPSEAT 1999, 2002]

(1) – 2

(2) – 1

(3) – 1/2

(4) – 1/4

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One mole of N2H4 loses 10 mole of electrons to form a new compound Y. Assuming that all nitrogen appear in the new compound, what is the oxidation state of N2 in Y ? (There is no change in the oxidation state of hydrogen) [IIT 1981; Pb. PMT 1998]

(1) + 3

(2) – 3

(3) – 1

(4) + 5

Concept Questions :-

Introduction to Redox
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The compound ${\mathrm{YBa}}_{2}{\mathrm{Cu}}_{3}{\mathrm{O}}_{7}$ which shows superconductivity has copper in oxidation state ........ Assume that the rare earth element Yttrium is in its usual +3 oxidation state [IIT 1994]

(1) 3/7

(2) 7/3

(3) 3

(4) 7

Concept Questions :-

Balancing of Equation by Oxidation Number
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In a balanced equation ${H}_{2}S{O}_{4}+x\text{\hspace{0.17em}}HI\to {H}_{2}S+y\text{\hspace{0.17em}}{I}_{2}+z\text{\hspace{0.17em}}{H}_{2}O$, the values of x, y, z are [EAMCET 2003]

(1) x = 3, y = 5, z = 2

(2) x = 4, y = 8, z = 5

(3) x = 8, y = 4, z = 4

(4) x = 5, y = 3, z = 4

Concept Questions :-

Balancing of Equation by Oxidation Number
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When $Mn{O}_{2}$ is fused with KOH, a coloured compound is formed, the product and its colour is [IIT Screening 2003]

(1) ${K}_{2}Mn{O}_{4}$, purple green

(2) $KMn{O}_{4}$, purple

(3) $M{n}_{2}{O}_{3}$, brown

(4) $M{n}_{3}{O}_{4}$ black

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If 1.2 g of metal displace 1.12 litre hydrogen at normal temperature and pressure, equivalent weight of metal would be [DPMT 2001]

(1) 24

(2) 12

(3) 1.2 $÷$ 11.2

(4) 1.2 $×$ 11.2

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In the equation

${H}_{2}S+2HN{O}_{3}\to 2{H}_{2}O+2N{O}_{2}+S$

The equivalent weight of hydrogen sulphide is [BVP 2003]

(1) 16

(2) 68

(3) 34

(4) 17