# NEET Chemistry Redox Reactions Questions Solved

The oxidation number of S in H2S2O8 is [MP PET 2002]

(1) + 2

(2) + 4

(3) + 6

(4) + 7

(3) The chemical structure of H2S2O8 is as follows:-

$H-O-\underset{O}{\overset{O}{\underset{||}{\overset{||}{S}}}}-O-O-\underset{O}{\overset{O}{\underset{||}{\overset{||}{S}}}}-O-H$

So the oxidation number of S should be :

$\underset{\left(for H\right)}{2×\left(+1\right)}+\underset{\left(for S\right)}{2×X}+\underset{\left(for O\right)}{6×\left(-2\right)}+\underset{\left(for O-O\right)}{2×\left(-1\right)}=0$ or X = +6.

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