NEET Chemistry Redox Reactions Questions Solved


The oxidation number of S in H2S2O8 is [MP PET 2002]

(1) + 2

(2) + 4

(3) + 6

(4) + 7

(3) The chemical structure of H2S2O8 is as follows:-

HOS||||OOOOS||||OOOH

So the oxidation number of S should be :

2×(+1)(for  H)+2×X(for  S)+6×(2)(for  O)+2×(1)(for  OO)=0 or X = +6.

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