For the equilibrium of the reaction, HgO(s) Hg(g) + 12O2(g), kP for the reaction at total pressure of P is:

(1) KP=233/2p3/2

(2) KP=231/2p1/2

(3) KP=132/3p3/2

(4) KP=132/3p

Concept Videos :-

#3 | Relation b/w two or more Equilibrium Constatnts
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Concept Questions :-

KP/KC - Factors

(1) HgO(s) Hg (g) + 12O2 (g)

Kp = PHg(g) × (PO2) 12

Total moles at equilibrium = 3x2

PHg = x3x / 2=P=23P

PO2 = x/23x/2P=13P

Kp = 23P13P1/2=233/2P3/2

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