The phase difference between the current and voltage of LCR circuit in series combination at resonance is 

(1) 0

(2) π/2

(3) π

(4) –π

In a series LCR circuit, resistance R = 10Ω and the impedance Z = 20Ω. The phase difference between the current and the voltage is 

(1) 30°

(2) 45°

(3) 60°

(4) 90°

In an ac circuit the reactance of a coil is \(\sqrt{3}\) times its resistance, the phase difference between the voltage across the coil to the current through the coil will be:
1. \( \pi / 3 \)
2. \( \pi / 2 \)
3. \( \pi / 4 \)
4. \( \pi / 6\)

The capacity of a pure capacitor is 1 farad. In dc circuits, its effective resistance will be 

(1) Zero

(2) Infinite

(3) 1 ohm

(4) 1/2 ohm

In an LCR circuit, the potential difference between the terminals of the inductance is 60 V, between the terminals of the capacitor is 30 V and that between the terminals of the resistance is 40 V. The supply voltage will be equal to:

1. 50 V

2. 70 V

3. 130 V

4. 10 V

In an LR-circuit, the inductive reactance is equal to the resistance R of the circuit. An e.m.f. $E=E_0\cos \left(\omega t\right)$ applied to the circuit. The power consumed in the circuit is:

(1) $\frac{E_0^2}{R}$

(2) $\frac{E_0^2}{2R}$

(3) $\frac{E_0^2}{4R}$

(4) $\frac{E_0^2}{8R}$

In the circuit given below, what will be the reading of the voltmeter 

(1) 300 V

(2) 900 V

(3) 200 V

(4) 400 V

For a series RLC circuit, R = X_L = 2X_C. The impedance of the circuit and phase difference between V and i will be:

1. $\frac{\sqrt{5}R}{2},$ ${\tan }^{-1}\left(2\right)$

2. $\frac{\sqrt{5}R}{2},{\tan }^{-1}\left(\frac{{\displaystyle 1}}{{\displaystyle 2}}\right)$

3. $\sqrt{5}{X}_C,{\tan }^{-1}\left(2\right)$

4. $\sqrt{5}R,$ ${\tan }^{-1}\left(\frac{{\displaystyle 1}}{{\displaystyle 2}}\right)$

In the adjoining ac circuit the voltmeter whose reading will be zero at resonance is

(1) V₁

(2) V₂

(3) V₃

(4) V₄

In the adjoining figure, the impedance of the circuit will be:

(1) 120 ohm

(2) 50 ohm

(3) 60 ohm

(4) 90 ohm