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If a current I given by ${I}_{0}\mathrm{sin}\text{\hspace{0.17em}}\left(\omega \text{\hspace{0.17em}}t-\frac{\pi }{2}\right)$ flows in an ac circuit across which an ac potential of $E={E}_{0}\mathrm{sin}\omega \text{\hspace{0.17em}}t$ has been applied, then the power consumption P in the circuit will be

(1) $P=\frac{{E}_{0}{I}_{0}}{\sqrt{2}}$

(2) $P=\sqrt{2}{E}_{0}{I}_{0}$

(3) $P=\frac{{E}_{0}{I}_{0}}{2}$

(4) P = 0