NEET Questions Solved


The magnitude of the earth’s magnetic field at a place is B0 and the angle of dip is δ. A horizontal conductor of length l lying along the magnetic north-south moves eastwards with a velocity v. The emf induced across the conductor is 

(1) Zero

(2) B0lv sin δ

(3) B0lv

(4) B0lv cos δ

(2) When a conductor lying along the magnetic north-south, moves eastwards it will cut vertical component of B0. So induced emf

e=vBVl=v(B0sinδl)=B0lvsinδ

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