A force F=(5i^+3j^+2k^)N is applied over a particle which displaces it from its origin to the point r=(2i^j^)m. The work done on the particle in joules is 

(1) – 7

(2) +7

(3) +10

(4) +13

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#1 | Work: Definition
#2 | Solved Problems

Concept Questions :-

Concept of work

(2) W=F.r=(5i^+3j^+2k^).(2i^j^)=103=7J   

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