The Van't Hoff factor for 0.1 M Ba(NO3)2 solution is 2.74. The degree of dissociation is [IIT 1999]

(1) 91.3%

(2) 87%

(3) 100%

(4) 74%

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#6 | Van't Hoff Factor & Abnormal Molecular Mass

Concept Questions :-

Van’t Hoff Factor

(2)           Ba(NO3)2Initial         0.1         At. eq.    (0.1x)Ba++0xM+2NO302xm

i=(0.1x)+x+2x0.1=0.1+2x0.1=2.74=0.1+2x=0.274 or x=0.1742=0.087

%α=x0.1×100=0.0870.1×100=87%  

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