The molarity of a 0.2NNa2CO3 solution will be [MP PMT 1987]

(1) 0.05 M

(2) 0.2 M

(3) 0.1 M

(4) 0.4 M

Concept Videos :-

#1 | Concentration of Solution: I
#2 | Concentration of Solution: II

Concept Questions :-

Concentration Term and Numericals

(3) N=M×molecular mass (M2)Equivalent mass (E)

So, M=N×Equivalent mass (E)Molecular mass (M2)

Equivalent mass of salt =Molecular massTotal positive valency

Equivalent mass of Na2CO3=M22

M=0.2×M2/2M2; M=0.22 = 0.1 M 

Difficulty Level:

  • 14%
  • 15%
  • 54%
  • 18%