NEET Chemistry Chemical Kinetics Questions Solved

NEET - 2008

The rate constants k1 and k2 for two different reactions are 1016e-2000/T and 1015e-1000/T  , respectively. The temperature at which k1=k2 is:

(a) 1000 K
(b) 20002.303K
(c) 2000K
(d) 10002.303K

 

(d) Key Idea: The Arrhenius equation is represented as

                  k = Ae-EaRT

In the given equations, first take log and then compare them.

                  k1 = 1016e-2000Tk2 = 1015e-1000T

On taking log, we get

log k1 = log 1016 - 20002.303T             ...(i)log k2 = log 1015 - 10002.303T             ...(ii)                             k1=k2Hence, from EQS (i) and (ii)                           T = 10002.303k

Difficulty Level:

  • 21%
  • 31%
  • 11%
  • 39%