The pair of species with the same bond order is:

(a) O22-, B2

(b) O2+, NO+

(c) NO, CO

(d) N2, O2

Concept Videos :-

#17 | MOT| Linear Combination of Atomic Orbitals
#18 | MOT| Formation of Bonding & Anti|Bonding Orbitals
#19 | MOT| Molecular Orbital Diagram

Concept Questions :-

O22- (8+8+2=18)

 = σ1s2, σ*1s2, σ2s2, σ*2s2, σ2pz2, π2px2π*2py2, π2px2π*2py2

Bond order (BO) = (Nb -Na)/2 = (10-8)/2 =1

B2 (5+5=10) = σ1s2, σ*1s2, σ2s2, σ*2s2, π2px1π*2py1

 

 

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