NEET Chemistry The Solid State Questions Solved

NEET - 2016

The ionic radii of A+ and B- ions are 0.98 x 10-10 m and 1.81 x10-10 m.  The coordination number of each ion in AB is.

(a) 4

(b) 8

(c) 2

(d) 6

 

Concept Videos :-

#5 | Simple Cubic Unit Cell: Coordination Number
#10 | FCC Unit Cell: Coordination Number
#15 | Tetrahedral Voids
#16 | Octahedral Voids
#17 | Position of Tetrahedral Voids in FCC
#18 | Position of Octahedral Voids in FCC
#19 | Hexagonal Primitive (HP) Unit Cell
#22 | Coordination Number of HP Unit Cel
#23 | Radius Ratio

Concept Questions :-

Voids and radius ratio/coordination number

(d) Given, ionic radius of cation(A+) = 0.98 x 10-10m

lonic radius of anion(B-) = 1.81 x 10-10 m

Coordination number of each ion in AB = ?

Now, we have

Radius ratio = Radius of cationRadius of anion = 0.98 × 10-10m1.81 × 10-10m= 0.541

If radius ratio range is in between 0.441 -0.732, ion would have octahedral structure with coordination number 'six'.

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