NEET Chemistry The Solid State Questions Solved

NEET - 2016

The ionic radii of A⁺ and B^- ions are 0.98 x 10^-10 m and 1.81 x10^-10 m. The coordination number of each ion in AB is.

(a) 4

(b) 8

(d) 6

Concept Videos :-

#5 | Simple Cubic Unit Cell: Coordination Number

#10 | FCC Unit Cell: Coordination Number

#15 | Tetrahedral Voids

#16 | Octahedral Voids

#17 | Position of Tetrahedral Voids in FCC

#18 | Position of Octahedral Voids in FCC

#19 | Hexagonal Primitive (HP) Unit Cell

#22 | Coordination Number of HP Unit Cel

#23 | Radius Ratio

Concept Questions :-

Voids and radius ratio/coordination number

(d) Given, ionic radius of cation(A⁺) = 0.98 x 10^-10m

lonic radius of anion(B^-) = 1.81 x 10^-10 m

$∴$ Coordination number of each ion in AB = ?

Now, we have

$Radius ratio = \frac{Radius of cation}{Radius of anion} = \frac{0.98 \times 10^{- 10} m}{1.81 \times 10^{- 10} m} = 0.541$

If radius ratio range is in between 0.441 -0.732, ion would have octahedral structure with coordination number 'six'.

Difficulty Level:

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