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Q. No.The cause of Klinefelter's syndrome in humans is :
1. Absence of Y-chromosome
2. Absence of X-chromosome
3. Extra copy of an autosome
4. Extra copy of an X-chromosome
Subtopic: Sex Aneuploidy - Turner & Klinefelter Syndrome |
83%
Level 1: 80%+
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Select the incorrect pair :
| 1. | Polygenic inheritance | Haemophilia |
| 2. | Linkage | Drosophila |
| 3. | Incomplete dominance | Antirrhinum |
| 4. | Pleiotropy | Phenylketonuria |
Subtopic: Polygenic Inheritance & Pleiotropy | Chromosomal Basis of Inheritance: Introduction | Linkage | Mendelian Disorders: Hemophilia |
83%
Level 1: 80%+
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According to Mendel, the nature of the unit factors that control the expression of traits were :
1. Stable
2. Blending
3. Stable and discrete
4. Discrete
1. Stable
2. Blending
3. Stable and discrete
4. Discrete
Subtopic: Chromosomal Basis of Inheritance: Introduction | Chromosomal Basis of Inheritance: Further Considerations |
82%
Level 1: 80%+
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Which of the following animals exhibit male heterogamety?
(i) Fruit fly
(ii) Fowl
(iii) Human
(iv) Honey bee
1. (i) and (iii)
2. (ii) and (iv)
3. (ii) and (iii)
4. (i) and (iv)
(i) Fruit fly
(ii) Fowl
(iii) Human
(iv) Honey bee
1. (i) and (iii)
2. (ii) and (iv)
3. (ii) and (iii)
4. (i) and (iv)
Subtopic: Sex Determination |
81%
Level 1: 80%+
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The probability of all possible genotypes of offsprings in a genetic cross can be obtained with the help of :
1. Test cross
2. Back cross
3. Punnett square
4. Linkage cross
1. Test cross
2. Back cross
3. Punnett square
4. Linkage cross
Subtopic: Monohybrid Cross: 1 | Monohybrid Cross: Further Understanding |
70%
Level 2: 60%+
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The number of different type of gametes that would be produced from a parent with genotype AABBCc is:
1. 1
2. 2
3. 3
4. 4
1. 1
2. 2
3. 3
4. 4
Subtopic: Monohybrid Cross: 1 | Dihybrid Cross Analysis |
73%
Level 2: 60%+
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| Assertion (A): | Accumulation of phenylalanine in the brain results in mental retardation in Phenylketonuria. |
| Reason (R): | The affected person lacks phenylalanine which is therefore not converted to tyrosine. |
In light of the above statements choose answer from the options given below:
| 1. | Both (A) and (R) are true and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are true but (R) is not the correct explanation of (A). |
| 3. | (A) is true, but (R) is false |
| 4. | (A) is false, but (R) are true. |
Subtopic: Mendelian Disorders |
Level 3: 35%-60%
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In Pisum sativum, the flower position may be axial (allele A) or terminal (allela a). What would be the percentage of the offspring with respect to axial flower position, if a cross is made between parents \(Aa \times aa\) ?
1. 25%
2. 50%
3. 75%
4. 100%
1. 25%
2. 50%
3. 75%
4. 100%
Subtopic: Monohybrid Cross: Further Understanding |
86%
Level 1: 80%+
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In humans, rolling of tongue is an autosomal dominant trait (R). In a family both the parents have the trait of rolling tongue but their daughter does not show the trait, whereas the sons have the trait of rolling of tongue.
The genotypes of the family would be:
The genotypes of the family would be:
| Mother | Father | Daughter | Son | |
| 1. | Rr | Rr | rr | rr |
| 2. | Rr | Rr | rr | RR |
| 3. | rr | Rr | RR | rr |
| 4. | RR | rr | Rr | Rr |
Subtopic: Pedigree Analysis: More Examples |
82%
Level 1: 80%+
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Study the pedigree analysis of human given below and identify the type of inheritance along with an example :
1. Sex-linked recessive, Haemophilia
2. Sex-linked dominant, Vitamin D resistant rickets
3. Autosomal recessive, Sickle-cell anaemia
4. Autosomal dominant, Myotonic dystrophy
1. Sex-linked recessive, Haemophilia
2. Sex-linked dominant, Vitamin D resistant rickets
3. Autosomal recessive, Sickle-cell anaemia
4. Autosomal dominant, Myotonic dystrophy
Subtopic: Pedigree Analysis: More Examples |
67%
Level 2: 60%+
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