To achieve above conversion, the reagents used will be:

(a) O3/H2O2, HO-/                                 (b) HBr, alc. KOH, O3, LiAlH4, H+/

(c)  HBr, t-BuOK, O3, KMnO4

 

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0°CPCl5A70-80%(2) H(1) 3NaNH2, mineral oilB46%; Product (B) is:

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CH3CH2CCHliq.NH3NaNH2I

Product (K) of the above reaction is:

(a) 

(b) 

(c) 

(d) 

 

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CH3-CH2-CH2-CCH+LiHN2(A)(CH3)2SO4(B)

Give the structural formula of compound (B):

(a) CH3-(CH2)2-CC-SO3H

(b) CH3-(CH2)2-CC-CH3

(c)  CH3-(CH2)2-CC-CH2-O-OsO-H

(d) CH3-CH2-CC-CH2

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; This conversion can be achieved by:

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Which alkyne will give 3-ethylhexane on catalytic hydrogenation?

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                                       Lindlar
Br-(CH2)12-C CH
 (A)(B);Product (B) is :
                           NaNH2   Catalyst
1.2.
3.4. 


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Ph - C CHMeOHMeO- Major product of the reaction is:

(a) 

(b) 

(c) Ph - C C-OMe

(d) 

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            ClPh-C||-CH3 3NaNH2 (A)            Cl                         product ; Product (A) is:

 

(a) Ph-CH=CH2          (b) Ph-CCH              (c) Ph-CH2-CH3             (d) Ph-CCNa

                               

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To carry out above conversion, (A) and (B) respectively, are :

(a) NaNH2, Cl - CH2ーCH- CH- Br
(b) NaNH2, CH2-CH2-CH2-Br
(c) NaNH2, l-CH2ーCH2-CH2-Br
(d) NaNH2, I-CH2-CH2-CH2-I

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