NEET Questions Solved


Consider the circuits shown in the figure. Both the circuits are taking same current from battery but current through R in the second circuit is 110th of current through R in the first circuit. If R is 11 Ω, the value of R1

(1) 9.9 Ω

(2) 11 Ω

(3) 8.8 Ω

(4) 7.7 Ω

(1) In figure (b) current through R2=ii10=9i10

Potential difference across R2 = Potential difference across RR2×910i=R×i10 i.e. R2=R9=119Ω

Req=R2×R(R2+R)=119×111119+111=1110Ω

Total circuit resistance =1110+R1=R=11R1=9.9Ω

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