In a circuit 5 percent of total current passes through a galvanometer. If resistance of the galvanometer is G then value of the shunt is

(1) 19 G

(2) 20 G

(3) $\frac{G}{20}$

(4) $\frac{G}{19}$

(4) $\frac{{i}_{g}}{i}=\frac{S}{G+S}$

$\frac{5}{100}=\frac{S}{G+S}$

$S=\frac{G}{19}$

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