# NEET Questions Solved

A galvanometer has a resistance of 25 ohm and a maximum of 0.01 A current can be passed through it. In order to change it into an ammeter of range 10 A, the shunt resistance required is

(1) 5/999 ohm

(2) 10/999 ohm

(3) 20/999 ohm

(4) 25/999 ohm

(4) ${i}_{g}=i\frac{S}{G+S}$$0.01=10\frac{S}{25+S}$

$⇒\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}1000S=25+S$$S=\frac{25}{999}\Omega$

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