We have a galvanometer of resistance 25 Ω. It is shunted by a 2.5 Ω wire. The part of total current that flows through the galvanometer is given as

(1) $\frac{I}{{I}_{0}}=\frac{1}{11}$

(2) $\frac{I}{{I}_{0}}=\frac{1}{10}$

(3) $\frac{I}{{I}_{0}}=\frac{3}{11}$

(4) $\frac{I}{{I}_{0}}=\frac{4}{11}$

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In the adjoining circuit, the e.m.f. of the cell is 2 volt and the internal resistance is negligible. The resistance of the voltmeter is 80 ohm. The reading of the voltmeter will be

(1) 0.80 volt

(2) 1.60 volt

(3) 1.33 volt

(4) 2.00 volt

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A voltmeter has resistance of 2000 ohms and it can measure upto 2V. If we want to increase its range to 10 V, then the required resistance in series will be

(1) 2000 Ω

(2) 4000 Ω

(3) 6000 Ω

(4) 8000 Ω

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The ammeter A reads 2 A and the voltmeter V reads 20 V. the value of resistance R is (Assuming finite resistance's of ammeter and voltmeter)

(1) Exactly 10 ohm

(2) Less than 10 ohm

(3) More than 10 ohm

(4) We cannot definitely say

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The resistance of a galvanometer coil is R. What is the shunt resistance required to convert it into an ammeter of range 4 times

(1) $\frac{R}{5}$

(2) $\frac{R}{4}$

(3) $\frac{R}{3}$

(4) 4 R

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In the given figure, battery E is balanced on 55 cm length of potentiometer wire but when a resistance of 10 Ω is connected in parallel with the battery then it balances on 50 cm length of the potentiometer wire then internal resistance r of the battery is

(1) 1 Ω

(2) 3 Ω

(3) 10 Ω

(4) 5 Ω

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A galvanometer has a resistance of 25 ohm and a maximum of 0.01 A current can be passed through it. In order to change it into an ammeter of range 10 A, the shunt resistance required is

(1) 5/999 ohm

(2) 10/999 ohm

(3) 20/999 ohm

(4) 25/999 ohm

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In the circuit shown, a meter bridge is in its balanced state. The meter bridge wire has a resistance 0.1 ohm/cm. The value of unknown resistance X and the current drawn from the battery of negligible resistance is

(1) 6 Ω, 5 amp

(2) 10 Ω, 0.1 amp

(3) 4 Ω, 1.0 amp

(4) 12 Ω, 0.5 amp

Concept Questions :-

Meter bridge and potentiometer
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AB is a potentiometer wire of length 100 cm and its resistance is 10 ohms. It is connected in series with a resistance R = 40 ohms and a battery of e.m.f. 2 V and negligible internal resistance. If a source of unknown e.m.f. E is balanced by 40 cm length of the potentiometer wire, the value of E is

(1) 0.8 V

(2) 1.6 V

(3) 0.08 V

(4) 0.16 V

Concept Questions :-

Meter bridge and potentiometer
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The measurement of the voltmeter in the following circuit is :

(1) 2.4 V

(2) 3.4 V

(3) 4.0 V

(4) 6.0 V

Concept Questions :-

Kirchoff's voltage law