# NEET Questions Solved

Two cells when connected in series are balanced on 8m on a potentiometer. If the cells are connected with polarities of one of the cell is reversed, they balance on 2m. The ratio of e.m.f.'s of the two cells is

(1) 3 : 5

(2) 5 : 3

(3) 3 : 4

(4) 4 : 3

(2) $\frac{{E}_{1}}{{E}_{2}}=\frac{{l}_{1}+{l}_{2}}{{l}_{1}-{l}_{2}}=\frac{\left(8+2\right)}{\left(8-2\right)}=\frac{5}{3}$

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