NEET Questions Solved

PMT - 1994

In order to pass 10% of main current through a moving coil galvanometer of 99 ohm, the resistance of the required shunt is 

(1) 9.9 Ω

(2) 10 Ω

(3) 11 Ω

(4) 9 Ω

(3) Shunt resistances S=igG(iig)=10×99(10010)=11Ω  

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