# NEET Questions Solved

The maximum power drawn out of the cell from a source is given by (where r is internal resistance)

(1) ${E}^{2}/2r$

(2) ${E}^{2}/4r$

(3) ${E}^{2}/r$

(4) ${E}^{2}/3r$

(2) $i=\frac{E}{r+R}$$P={i}^{2}\text{\hspace{0.17em}}R$$P=\frac{{E}^{2}R}{{\left(r+R\right)}^{2}}$

Power is maximum when r = R${P}_{\mathrm{max}}={E}^{2}/4r$

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