# NEET Questions Solved

The number of dry cells, each of e.m.f. 1.5 volt and internal resistance 0.5 ohm that must be joined in series with a resistance of 20 ohm so as to send a current of 0.6 ampere through the circuit is

(1) 2

(2) 8

(3) 10

(4) 12

(3) In series $i=\frac{nE}{nr+R}$

$0.6=\frac{n×1.5}{n×0.5×20}$n = 10

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