# NEET Questions Solved

PMT - 2004

In circuit shown below, the resistances are given in ohms and the battery is assumed ideal with emf equal to 3 volt. The voltage across the resistance R4 is

(1) 0.4 V

(2) 0.6 V

(3) 1.2 V

(4) 1.5 V

(1) Equivalent resistance of the given network ${R}_{eq}=75\text{\hspace{0.17em}}\Omega$

∴ Total current through battery $i=\frac{3}{75}$

${i}_{1}={i}_{2}=\frac{3}{75×2}=\frac{3}{150}$

Current through ${R}_{4}=\frac{3}{150}×\frac{60}{\left(30+60\right)}=\frac{3}{150}×\frac{60}{90}=\frac{2}{150}A$

${V}_{4}={i}_{4}×{R}_{4}=\frac{2}{150}×30=\frac{2}{5}V=0.4\text{\hspace{0.17em}}V$

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