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Two wires of same metal have the same length but their cross-sections are in the ratio 3 : 1. They are joined in series. The resistance of the thicker wire is 10 Ω. The total resistance of the combination will be

(1) 40 Ω

(2) $\frac{40}{3}\Omega$

(3) $\frac{5}{2}\Omega$

(4) 100 Ω

PMT