NEET Questions Solved

PMT - 1994

A battery of e.m.f. 10 V is connected to resistance as shown in figure. The potential difference VAVB  between the points A and B is 

(1) –2 V

(2) 2 V

(3) 5 V

(4) 2011V

(2) Req=5Ω, Current i=105=2A and current in each branch = 1A

Potential difference between C and A,

VCVA=1×1=1V .......(i)

Potential difference between C and B,

VCVB=1×3=3V ......(ii)

On solving (i) and (ii) VAVB=2volt

Short Trick : (VAVB)=i2(R2R1)=22(31)=2V

Difficulty Level:

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