# NEET Questions Solved

PMT - 1984

Two resistors are connected (a) in series (b) in parallel. The equivalent resistance in the two cases are 9 ohm and 2 ohm respectively. Then the resistances of the component resistors are

(1) 2 ohm and 7 ohm

(2) 3 ohm and 6 ohm

(3) 3 ohm and 9 ohm

(4) 5 ohm and 4 ohm

(2) ${R}_{1}+{R}_{2}=9$ and $\frac{{R}_{1}{R}_{2}}{{R}_{1}+{R}_{2}}=2$${R}_{1}{R}_{2}=18$

${R}_{1}-{R}_{2}=\sqrt{{\left({R}_{1}+{R}_{2}\right)}^{2}-4{R}_{1}{R}_{2}}=\sqrt{81-72}=3$

${R}_{1}=6\Omega ,\text{\hspace{0.17em}}{R}_{2}=3\Omega$

Difficulty Level:

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