NEET Questions Solved

PMT - 1984

Two resistors are connected (a) in series (b) in parallel. The equivalent resistance in the two cases are 9 ohm and 2 ohm respectively. Then the resistances of the component resistors are 

(1) 2 ohm and 7 ohm

(2) 3 ohm and 6 ohm

(3) 3 ohm and 9 ohm

(4) 5 ohm and 4 ohm

(2) R1+R2=9 and R1R2R1+R2=2R1R2=18

R1R2=(R1+R2)24R1R2=8172=3

R1=6Ω,R2=3Ω  

Difficulty Level:

  • 13%
  • 73%
  • 12%
  • 5%
Crack NEET with Online Course - Free Trial (Offer Valid Till September 23, 2019)