# NEET Chemistry The Solid State Questions Solved

Caculate the distance between 111 planes in a crystal of Ca. Repeat the calculation for the 222 planes. (a = 0.556nm)

(1) 016.1 nm

(2) 01.61 nm

(3) 0.610 nm

(4) None of the above

(2) We have, $d=\frac{a}{\sqrt{{h}^{2}+{k}^{2}+{\ell }^{2}}}$; ${d}_{111}=\frac{0.556}{\sqrt{{1}^{2}+{1}^{2}+{1}^{2}}}=0.321nm$

The separation of the 111 planes is twice as great as that of 222 planes.

Difficulty Level:

• 16%
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