# NEET Chemistry The Solid State Questions Solved

A transition Metal Mcan exist in two oxidation states +2 and +3.It forms an oxide whose experimentalformula is given by MxO where x < 1. Then the ratio of metal ions in +3 state to those in +2 state in oxide is given by :

(1) $\frac{1-x}{1+x}$

(2) 1 + 2X

(3) 1 + $\frac{x}{2}$

(4) $\frac{2\left(x-1\right)}{3x-2}$

(4) In 1 mole of MxO, mole of M2+ ion = y

∴ mole of M3+ ion = x – y.

Applying charge balance, 2y + 3(x – y) – 2 = 0

⇒ y = 3x – 2

$\frac{{\text{M}}^{\text{3+}}}{{\text{M}}^{\text{2+}}}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}\frac{\text{x\hspace{0.17em}}-\text{\hspace{0.17em}y}}{\text{y}}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}\frac{\text{x\hspace{0.17em}}-\text{\hspace{0.17em}}\left(3\text{x\hspace{0.17em}}-\text{\hspace{0.17em}}2\right)}{3\text{x\hspace{0.17em}}-\text{\hspace{0.17em}}2}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}\frac{2\left(\text{x\hspace{0.17em}}-\text{\hspace{0.17em}}1\right)}{3\text{x\hspace{0.17em}}-\text{\hspace{0.17em}}2}$

Difficulty Level:

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