NEET Chemistry The Solid State Questions Solved

A crystal is made of particle X, Y & Z. X forms FCC packing, Y occupies all octahedral voids of X and Zoccupies all tetrahedral voids of X, if all the pariticles along one body diagonal are removed then the formula of the crystal would be –

(1) XYZ2

(2) X2YZ2

(3) X5Y4Z5

(4) X5Y4Z8

(1) When all particle along are body diagonal one removed, these 2 X atoms from corner are removed, one Y particle removed & 2 Z particle removed.

Hence new arrangement, X particle = $\frac{1}{8}\text{\hspace{0.17em}}×\text{\hspace{0.17em}}6\text{\hspace{0.17em}}+\text{\hspace{0.17em}}\frac{1}{2}\text{\hspace{0.17em}}×\text{\hspace{0.17em}}6\text{\hspace{0.17em}}=\text{\hspace{0.17em}}\frac{15}{4}$; Y particle = 6 ; Z particle = 3

Hence formula = X15/4Y3Z6 = X5/4YZ6 = X5Y4Z8

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