# NEET Questions Solved

PMT - 2001

A player caught a cricket ball of mass 150 gm moving at a rate of 20 m/s. If the catching process be completed in 0.1 s, then the force of the blow exerted by the ball on the hands of the player is

(1) 0.3 N

(2) 30 N

(3) 300 N

(4) 3000 N

(2) Force exerted by the ball on hands of the player

$=\frac{mdv}{dt}=\frac{0.15×20}{0.1}=30\text{\hspace{0.17em}}N$

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