Read the following road map carefully

(1) Both the ethers obtained by the two routes have opposite but equal optical rotation.

(2) One of the ether is obtained as a racemic mixture.

(3) Step II & III both are SN2 reaction and both have inversion.

(4) Step II has inversion but step III has retention.

$\text{PhOH\hspace{0.17em}}\underset{\text{NaOH}}{\overset{{\text{Me}}_{\text{2}}{\text{SO}}_{\text{4}}}{\to }}\text{\hspace{0.17em}P,}$ P is

(1) Ph–O–SO₂OMe

(2) PhOMe

(3) PhOSO₂OPh

(4) PhMe

Which of the following statement is correct

(1)
(2)
(3)
(4)

Product is

(1) CH₃ – CH₂ – S – CH₂ – CH₂ – OH

(2) CH₃ – CH₂ – O – CH₂ – CH₂ – OH

(3)

(4)

Product, Product is

(1)
(2)
(3)
(4)

In the reaction The product is –

1.
2.
3.
4.

(CH₃)₃CCI + (CH₃)₃C${\mathrm{O}}^{-}$ K⁺ → Product

1. S_N Product will be more

2. E₂ Product will be more

3. Both will be the same

4. None of the above

Neopentyl iodide is treated with aq. AgNO₃ solution, a yellow precipitate is formed along with another compound which is

1. (CH₃)₃CCH₂ONO₂

2. 

3. (CH₃)₃CCH₂OH

4. 

The major end product of the following reaction is

1.
2.
3.
4.

Z