# NEET Chemistry Redox Reactions Questions Solved

One gm. of a metal carbonate gave 0.56 gm. of its oxide on heating. The equivalent mass of the metal is

(1) 40

(2) 30

(3) 20

(4) 10

(3) or $\frac{1.0}{0.56}\text{\hspace{0.17em}}=\text{\hspace{0.17em}}\frac{E\text{\hspace{0.17em}}+\text{\hspace{0.17em}}30}{E\text{\hspace{0.17em}}+\text{\hspace{0.17em}}8}$

or $\left(E\text{\hspace{0.17em}}+\text{\hspace{0.17em}}8\right)\text{\hspace{0.17em}\hspace{0.17em}}×\text{\hspace{0.17em}}1.0\text{\hspace{0.17em}}=\text{\hspace{0.17em}}\left(E\text{\hspace{0.17em}}+\text{\hspace{0.17em}}30\right)\text{\hspace{0.17em}}\left(0.56\right)$ (Where E is the equivalent mass of the metal)

E = 20

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