NEET Chemistry Redox Reactions Questions Solved


An excess of NaOH was added to 100 mL of a ferric chloride solution. This caused the precipitation of 1.425 g of Fe(OH)3. Calculate the normality of the ferric chloride solution

(1) 0.20 N

(2) 0.50 N

(3) 0.25 N

(4) 0.40 N

(4) 3 NaOH + FeCl3 → Fe(OH)3 + 3NaCl

m.e. of NaOH = me.e of Fe(OH)3

100 × N = WE×1000(EFe(OH)3=mol. wt.3)

N = 1.425×10×3107 = 0.3999 = 0.4 N

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