Select Question Set:
Q. No.Young's double-slit experiment is conducted with light of wavelength \(\lambda.\) The double-slit is shifted towards the source by a distance \(L,\) and the position of the \(5^{\text{th}}\) fringe is shifted by:
1.
\(\dfrac{5\lambda D}{d}\)
2.
\(\dfrac{5\lambda L}{d}\)
3.
\(\dfrac{5\lambda (L+D)}{d}\)
4.
\(\dfrac{5\lambda (L-D)}{d}\)
Subtopic: Young's Double Slit Experiment |
Level 3: 35%-60%
Hints
In a Young's double-slit experiment with identical slits (of slit separation-\(d,\) slit to screen distance \(D\)), the phase difference between the waves arriving at a point just opposite to one of the slits is \(\dfrac{\pi}{2}.\) The source is placed symmetrically with respect to the slits. The wavelength of light is:
| 1. | \(\dfrac{2d^2}{D}\) | 2. | \(\dfrac{d^2}{2D}\) |
| 3. | \(\dfrac{d^2}{D}\) | 4. | \(\dfrac{D^2}{d}\) |
Subtopic: Young's Double Slit Experiment |
56%
Level 3: 35%-60%
Hints
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
Sound waves travel faster in water than in air. Imagine a plane sound wavefront incident at an angle \(\alpha\) at the air-water interface; the refracted wavefront making an angle \(\beta\) with the interface. Then,
| 1. | \(\alpha>\beta\) |
| 2. | \(\beta>\alpha\) |
| 3. | \(\alpha=\beta\) |
| 4. | the relation between \(\alpha~\&~\beta \) cannot be predicted. |
Subtopic: Huygens' Principle |
Level 3: 35%-60%
Hints
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
Young's double-slit experiment is conducted with light of an unknown wavelength, the waves arriving at the central point on the screen are found to have a phase difference of \(\dfrac{\pi}{2}.\) The closest maximum to the central point is formed behind one of the slits. The separation between the slits is \(d,\) and the slit to screen separation is \(D.\) The longest wavelength for this to happen is:
| 1. | \(\dfrac{2d^2}{D}\) | 2. | \(\dfrac{2d^2}{3D}\) |
| 3. | \(\dfrac{d^2}{2D}\) | 4. | \(\dfrac{d^2}{6D}\) |
Subtopic: Young's Double Slit Experiment |
Level 3: 35%-60%
Hints
Young's double-slit experiment is performed with identical slits separated by a distance \(d,\) and with light of wavelength \(\lambda.\) The screen is placed at a point which is at a distance \(D\) from the double-slit, as usual. A convex lens of focal length \(f\) is inserted between the double-slit and the screen, very close to the double slit. The screen is adjusted (i.e. the value of \(D\) is slowly varied) until a clear interference pattern is formed. The fringe width equals:
| 1. | \(\dfrac{\lambda f}{d}\) | 2. | \(\dfrac{2\lambda f}{d}\) |
| 3. | \(\dfrac{\lambda f}{2d}\) | 4. | \(\dfrac{\lambda f}{d\sqrt2}\) |
Subtopic: Young's Double Slit Experiment |
59%
Level 3: 35%-60%
Hints
Electrons (mass \(m\)) moving with a velocity \(v\) are incident normally onto a single slit of width \(d,\) and are detected on a screen placed at a distance \(D\) behind the slit. The central point on the screen where most of the electrons are detected is \(O.\) The closest point to \(O\) where no electrons are detected is \(X.\) Then \(OX\) equals:
| 1. | \(\dfrac{hD}{mvd}\) | 2. | \(\dfrac{hD}{2mvd}\) |
| 3. | \(\dfrac{2hD}{mvd}\) | 4. | \(\dfrac{3hD}{2mvd}\) |
Subtopic: Diffraction |
60%
Level 2: 60%+
Hints
In a Young's double-slit experimental setup, \(240\) fringes are observed to be formed in a region of the screen when light of wavelength \(450\) nm is used. If the wavelength of light is changed to \(600\) nm, the number of fringes formed in the same region will be:
| 1. | \(135\) | 2. | \(180\) |
| 3. | \(320\) | 4. | \(428\) |
Subtopic: Young's Double Slit Experiment |
74%
Level 2: 60%+
Hints
Young's double-slit experiment is conducted with the light of wavelength, \(\lambda=4500~\mathring A\) and \(400\) fringes are observed in a \(10\) cm region on the screen. The apparatus is immersed in a clear liquid of refractive index \(\mu=2.\) The number of fringes observed will be:
1. \(400\)
2. \(800\)
3. \(200\)
4. \(1600\)
1. \(400\)
2. \(800\)
3. \(200\)
4. \(1600\)
Subtopic: Young's Double Slit Experiment |
64%
Level 2: 60%+
Hints
A parallel beam of light of wavelength \(\lambda\) is incident normally on a single slit of width \(d,\) and a pattern of maxima and minima are observed on a screen placed far behind the slit. The first minimum (nearest to the central maximum) is formed at an angle \(\theta,\) where \(\sin\theta=\)
| 1. | \(\dfrac{\lambda}{d}\) | 2. | \(\dfrac{\lambda}{2d}\) |
| 3. | \(\dfrac{2\lambda}{d}\) | 4. | \(\dfrac{\lambda}{4d}\) |
Subtopic: Diffraction |
67%
Level 2: 60%+
Hints
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
Light of wavelength \(\lambda\) falls perpendicularly onto a single slit of width \(d\). A diffraction maximum is formed at \(P\) on a faraway screen placed parallel to plane of the slit. The first diffraction minimum is formed at \(Q,\) as shown on the screen. Let \(C\) be a 'point' so that it divides the slit \(AB\) in the ratio \(\dfrac{AC}{CB}=\dfrac12,\) i.e. \(AC\) represents the upper \(\dfrac13^{rd}\) of the slit. The total amplitude of the oscillation arriving from \(AC\) at \(Q\) is \(A_1\) and from \(CB\) at \(Q\) is \(A_2\).
Then:
1. \(2 A_{1}=A_{2}\)
2. \(A_{1}=2 A_{2}\)
3. \(\sqrt{2} A_{1}=A_{2}\)
4. \(A_{1}=A_{2}\)
Then:
1. \(2 A_{1}=A_{2}\)
2. \(A_{1}=2 A_{2}\)
3. \(\sqrt{2} A_{1}=A_{2}\)
4. \(A_{1}=A_{2}\)
Subtopic: Diffraction |
Level 3: 35%-60%
Hints
Select Question Set:
© 2025 GoodEd Technologies Pvt. Ltd.