Position of a body with acceleration 'a' is given by x=Kamtn,here t is time. Find dimension of m and n

(1) m = 1, n = 1

(2) m = 1, n = 2

(3) m = 2, n = 1

(4) m = 2, n = 2

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(2) As x=Kam×tn

[M0LT0]=[LT2]m[T]n=[LmT2m+n]

m = 1 and 2m+n=0 n=2.

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