NEET Chemistry Chemical Kinetics Questions Solved


Two reactions of the same order have equal Pre-exponential factors but their activation energies differ by 24.9 kJ/mol. Calculate the ratio between the rate constants (K2/K1) these reactions at 27°C :

(1) 3 x 104

(2) 1/3 x 10-4

(3) 1/3 x 104

(4) 3 x 10-4

(1) log10K1 = log10A - Ea1/2.303RT   ----(1)

     log10K2 = log10A - Ea2/2.303RT   ----(2)

     log10(K2/K1) = (Ea1 - Ea2)/2.303RT

     = log10(K2/K1) = (24.9x1000) / (2.303x8.314x300)

     = K2/K1 = 2.99x104 = 3 x 104

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