NEET Chemistry Chemical Kinetics Questions Solved


How fast the reaction is at 25°C as compared to 0°C. If the activation energy is 65 KJ :-

(1) 2 times

(2) 5 times

(3) 11 times

(4) 16 times

(3) log k2/k1 = Ea/2.303R(1/T1 - 1/T2)

 

Rate of the reaction at 0° C temperature =k_1

T_1= 0^oC=273 K

Rate of the reaction at 25 °C temperature =k_2

T_1=25^oC=298K

E_a=65kJ=65000 J

\log\frac{k_2}{k_1}=\frac{E_a}{2.303\times r}(\frac{T_2-T_1}{T_2T_1})

\log\frac{k_2}{k_1}=\frac{65000 kJ}{2.303\times 8.314J /K}\frac{298K-273K}{298 K\times 273 K}

\log \frac{k_2}{k_1}=1.043

k_2=11.04\times k_1

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