Ostwald dilution law for weak electrolyte HA can be given as

$\left(1\right)<mspace\; width="1em"></mspace>{\mathrm{K}}_{\mathrm{a}}=\frac{{\mathrm{C\alpha }}^2}{(1-\mathrm{\alpha })}$
$\left(2\right)<mspace\; width="1em"></mspace>\mathrm{Ka}<mspace\; width="1em"></mspace>=<mspace\; width="1em"></mspace>{\mathrm{C\alpha }}^2<mspace\; width="1em"></mspace>\mathrm{if}<mspace\; width="1em"></mspace>\mathrm{\alpha }\to 0$
$\left(3\right)<mspace\; width="1em"></mspace>{\mathrm{K}}_{\mathrm{a}}<mspace\; width="1em"></mspace>=<mspace\; width="1em"></mspace>\frac{{\mathrm{C\lambda }}^2}{{\mathrm{\lambda }}^2({\mathrm{\lambda }}^2-\mathrm{\lambda })}$
$\left(4\right)<mspace\; width="1em"></mspace>\mathrm{All}<mspace\; width="1em"></mspace>\mathrm{of}<mspace\; width="1em"></mspace>\mathrm{the}<mspace\; width="1em"></mspace>\mathrm{above}$

If carbon dioxide is 2% dissociated at equilibrium 2CO₂ (g)$\rightleftharpoons$2CO(g) + O₂(g). The mole fraction of CO₂ at equuilibrium is

1. 1.01/0.98           

2. 0.98/1.01

3. 0.01/0.98           

4. 0.098/1.01

The amount of CaC₂O₄ (molecular weight =128) will dissolve in distilled water to make 1 liter of a saturated solution is: 

[K_sp (CaC₂O₄) = 2.5 x 10^-9 ]

1. 0.0064 g             
2. 0.1280 g
3. 0.0128 g           
4. 1.2800 g

$\frac{{\mathrm{K}}_{\mathrm{p}}}{{\mathrm{K}}_{\mathrm{c}}}$ for the gaseous reaction:

$\mathrm{I}.<mspace\; width="1em"></mspace>2\mathrm{A}<mspace\; width="1em"></mspace>+<mspace\; width="1em"></mspace>3\mathrm{B}<mspace\; width="1em"></mspace>\rightleftharpoons 2\mathrm{C}$
$\mathrm{II}.<mspace\; width="1em"></mspace>2\mathrm{A}\rightleftharpoons 4\mathrm{B}$
$\mathrm{III}.<mspace\; width="1em"></mspace>\mathrm{A}+\mathrm{B}+2\mathrm{C}<mspace\; width="1em"></mspace>\rightleftharpoons 4\mathrm{D}$

Would be respectively:

1. (RT)^-3, (RT)², (RT)⁰ 

2. (RT)^-3, (RT)-², (RT)^-1 

3. (RT)^-3, (RT)², (RT) 

4. None of the above

In which of the following reaction the value of K_p will be equal to K_c ?

$1.<mspace\; width="1em"></mspace>{\mathrm{N}}_2\left(\mathrm{g}\right)<mspace\; width="1em"></mspace>+<mspace\; width="1em"></mspace>{\mathrm{O}}_2\left(\mathrm{g}\right)<mspace\; width="1em"></mspace>\rightleftharpoons 2\mathrm{NO}\left(\mathrm{g}\right)$

$2.<mspace\; width="1em"></mspace>{\mathrm{PCl}}_5\left(\mathrm{g}\right)\rightleftharpoons {\mathrm{PCl}}_3\left(\mathrm{g}\right)<mspace\; width="1em"></mspace>+<mspace\; width="1em"></mspace>{\mathrm{Cl}}_2\left(\mathrm{g}\right)$

$3.<mspace\; width="1em"></mspace>2{\mathrm{NH}}_3\left(\mathrm{g}\right)\rightleftharpoons {\mathrm{N}}_2\left(\mathrm{g}\right)<mspace\; width="1em"></mspace>+3{\mathrm{H}}_2\left(\mathrm{g}\right)$

$4.<mspace\; width="1em"></mspace>2{\mathrm{SO}}_2\left(\mathrm{g}\right)<mspace\; width="1em"></mspace>+<mspace\; width="1em"></mspace>{\mathrm{O}}_2\left(\mathrm{g}\right)<mspace\; width="1em"></mspace>\rightleftharpoons 2{\mathrm{SO}}_3\left(\mathrm{g}\right)$

The pH of a solution obtained by mixing 50ml of 0.4N HCl and 50ml of 0.2M NaOH is:

1. 13

2. 12

3. 1.0

4. 2.0

A 50 ml solution of strong acid of pH = 1 is mixed with a 50 ml solution of strong acid of pH=2. The pH of the mixture will be nearly:                                                     

(log 5.5 = 0.74)

1. 0.74                   

2. 1.26

3. 3.76                 

4. 4.50

The molecule that is least likely to behave as Lewis base is: 

1. NH₃

2. BF₃

3. OH^-

4. H₂O

K_c and K_p are not equal for a reaction given below:

1. 2NO(g) $\rightleftharpoons$N₂(g) + O₂(g)

2. SO₂(g) + NO₂(g) $\rightleftharpoons$SO₃(g) + NO(g)

3. H₂(g) + I₂(g) $\rightleftharpoons$2HI(g)

4. 2C(s) + O₂(g) $\rightleftharpoons$2CO₂(g)

Which one of the following molecular hydrides acts as a Lewis acid?

1. NH₃         

2. H₂O         

3. B₂H₆           

4. CH₄