ENi+2Ni0 = -0.25 V, EAu+3Au0 = 1.50 Vthe emf of voltaic cellNi | Ni+2(1M) || Au+3(1M) Au is:-

(1) 1.25 V

(2) -1.75 V

(3) 1.75 V

(4) 4 V

Concept Videos :-

#6 | Nernst Equation
#7 | Problem Set 1 on Nernst Equation
#8 | Problem Set 2 on Nernst Equation

Concept Questions :-

Nernst Equation

(3) 

Ecell = (ESRP)c - (ESRP)a         = 1.50 -(-0.25) = 1.75 VEcell = 1.75 -0.0596 log (1)3(1)2        = 1.75 V

Difficulty Level:

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