Two men P & Q are standing at corners A & B of square ABCD of side 8 m. They start moving along the track with constant speed 2 m/s and 10 m/s respectively. The time when they will meet for the first time, is equal to:

(1) 2 sec

(2) 3 sec

(3) 1 sec

(4) 6 sec

Concept Questions :-

Relative motion in 1-D
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Difficulty Level:

A bullet loses $\frac{1}{20}$ of its velocity passing through a plank. The least number of planks required to stop the bullet is (All planks offers same retardation)

(1) 10

(2) 11

(3) 12

(4) 23

Concept Questions :-

Uniformly accelerated motion
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Difficulty Level:

A body starts from the origin and moves along the X-axis such that the velocity at any instant is given by $\left(4{t}^{3}-2t\right)$, where t is in sec and velocity in m/s. What is the acceleration of the particle, when it is 2 m from the origin ?

1. 28 m/s2

2. 22 m/s2

3. 12 m/s2

4. 10 m/s2

Concept Questions :-

Non-uniform acceleration
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Difficulty Level:

The relation between time and distance is $t=\alpha {x}^{2}+\beta x$, where α and β are constants. The retardation is

1. $2\alpha {v}^{3}$

2. $2\beta {v}^{3}$

3. $2\alpha \beta {v}^{3}$

4. $2{\beta }^{2}{v}^{3}$

Concept Questions :-

Instantaneous speed and instantaneous velocity
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Difficulty Level:

A point moves with uniform acceleration and v1, v2 and v3 denote the average velocities in the three successive intervals of time t1, t2 and t3. Which of the following relations is correct ?

(1) $\left({v}_{1}-{v}_{2}\right):\left({v}_{2}-{v}_{3}\right)=\left({t}_{1}-{t}_{2}\right):\left({t}_{2}+{t}_{3}\right)$

(2) $\left({v}_{1}-{v}_{2}\right):\left({v}_{2}-{v}_{3}\right)=\left({t}_{1}+{t}_{2}\right):\left({t}_{2}+{t}_{3}\right)$

(3) $\left({v}_{1}-{v}_{2}\right):\left({v}_{2}-{v}_{3}\right)=\left({t}_{1}-{t}_{2}\right):\left({t}_{1}-{t}_{3}\right)$

(4) $\left({v}_{1}-{v}_{2}\right):\left({v}_{2}-{v}_{3}\right)=\left({t}_{1}-{t}_{2}\right):\left({t}_{2}-{t}_{3}\right)$

Concept Questions :-

Uniformly accelerated motion
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Difficulty Level:

The acceleration of a moving body can be found from

(1) Area under velocity-time graph

(2) Area under distance-time graph

(3) Slope of the velocity-time graph

(4) Slope of distance-time graph

Concept Questions :-

Graphs
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Difficulty Level:

The initial velocity of a particle is u (at t = 0) and the acceleration f is given by at. Which of the following relation is valid

1. $v=u+a{t}^{2}$

2. $v=u+a\frac{{t}^{2}}{2}$

3. $v=u+at$

4. v = u

Concept Questions :-

Non-uniform acceleration
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Difficulty Level:

The initial velocity of the particle is 10 m/sec and its retardation is 2 m/sec2. The distance moved by the particle in 5th second of its motion is

(1) 1 m

(2) 19 m

(3) 50 m

(4) 75 m

Concept Questions :-

Uniformly accelerated motion
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Difficulty Level:

A motor car moving with a uniform speed of 20 m/sec comes to stop on the application of brakes after travelling a distance of 10 m Its acceleration is

(1) 20 m/sec2

(2) –20 m/sec2

(3) –40 m/sec2

(4) +2 m/sec2

Concept Questions :-

Uniformly accelerated motion
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Difficulty Level:

The velocity of a body moving with a uniform acceleration of 2 m/sec2 is 10 m/sec. Its velocity after an interval of 4 sec is

(1) 12 m/sec

(2) 14 m/sec

(3) 16 m/sec

(4) 18 m/sec

Concept Questions :-

Uniformly accelerated motion